вычислите интегралы. Created by alinasytnikova2004. algebra-ru

Ответ:Объяснение:Пусть 5x+6=u ⇒ du=5*dx dx=du/5.

вычислите интегралы...

alinasytnikova2004 @alinasytnikova2004

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вычислите интегралы

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sangers1959

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Ответ:

Объяснение:

$a)\\\int\limits^6_2 {\frac{dx}{\sqrt{5x+6} } }=0,8 .$

Пусть 5x+6=u ⇒ du=5*dx dx=du/5.

$\int\limits^6_2 {\frac{du}{5*\sqrt{u} } } =\frac{1}{5}*\int\limits^6_2 {u^{-\frac{1}{2} } \, du=\frac{2}{5} *u^{\frac{1}{2}}|_2^6=\frac{2}{5}*\sqrt{5x+6}|_2^6=\frac{2}{5}*(\sqrt{36}-\sqrt{16})=$

$=0,4*(6-4)=0,4*2=0,8.$

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Answers & Comments

Verified answer

dany vektory a 3i 5jk i bj 5k vychislite skalyarnoe proizvedenie a bi

dany koordinaty tochek a123 b32 1c58 1 najti koordinaty vektora ab

1.If I (work) in a film, I would earn more. 2.If she (fail) in her present job s...

pri kakom znachenii n dannye vektory perpendikulyarny a 7n3 v15n

vychislite integralyd531cd295487a286283749ba030cc224 95279

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