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jena0011
@jena0011
July 2022
2
11
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Вычислите массовую долю азота в соединении N2O5.
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achilles6eldor
N2O5 - 108 Mr
108---------100 %
28-----------x= 25,9 % N
0 votes
Thanks 2
burihon76
Mr(N2O5)= 28+80=128 г
128------------100%
28-------------Х% Х= 28*100/128=21,87%
1 votes
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Answers & Comments
108---------100 %
28-----------x= 25,9 % N
128------------100%
28-------------Х% Х= 28*100/128=21,87%