Ответ:

Объяснение:

Mr(Cl2O3) = 35,5*2 + 16*3 =119

W(Cl) = Ar(Cl) *n / Mr(Cl2O3)  *100% = 35,5*2 / 119  *100% =60%

W(O) = Ar(O) *n / Mr(Cl2O3)  *100% = 16*3 / 119  *100% = 40%

Mr(BaSO3) = 137 + 32 + 16*3 = 217

W(Ba) = Ar(Ba) *n / Mr(BaSO3)  *100% = 137*1 / 217  *100% =63%

W(S) = Ar(S) *n / Mr(BaSO3)  *100% = 32*1 / 217  *100% = 15%

W(O) = Ar(O) *n / Mr(BaSO3)  *100% = 16*3 / 217  *100% = 22%