Вычислите объём водорода,которая образуется при растворении алюминия массой 8.1 г в водном растворе щелочи
Если будет бред,то я буду удалять!!!
2Al+2NaOH+6H2O=2Na[Al(OH)4]+3H2
2 3
n(Al)=8,1/27=0,3моль; n(H2)=0,3*1,5=0,45моль; V(H2)=0,45*22,4=10,08л.
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Answers & Comments
2Al+2NaOH+6H2O=2Na[Al(OH)4]+3H2
2 3
n(Al)=8,1/27=0,3моль; n(H2)=0,3*1,5=0,45моль; V(H2)=0,45*22,4=10,08л.
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