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ilovemars
@ilovemars
October 2021
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вычислите сумму двух первых членов геометрической прогрессии
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B4=1/27
q=1/3
b4=b1q^3
b1=1
b2=1/3
S2=1+1/3=4/3
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mmb1
Verified answer
Б4=1/27,d=1/3,тогда б3=(1/27)/(1/3)=1/9,б2=(1/9)/(1/3)=1/3,б1=(1/3)/(1/3)=1
S=б1+б2=1+1/3=4/3
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Answers & Comments
q=1/3
b4=b1q^3
b1=1
b2=1/3
S2=1+1/3=4/3
Verified answer
Б4=1/27,d=1/3,тогда б3=(1/27)/(1/3)=1/9,б2=(1/9)/(1/3)=1/3,б1=(1/3)/(1/3)=1S=б1+б2=1+1/3=4/3