[tex]f(x) = \frac{ {x}^{2} + 2}{x - 3} \\ f'(x) = \frac{( {x}^{2} + 2)'(x - 3) - (x - 3)'( {x}^{2} + 2) }{(x - 3) {}^{2} } = \\ = \frac{2x(x - 3) - ( {x}^{2} + 2) }{(x - 3) {}^{2} } = \frac{2 {x}^{2} - 6x - {x}^{2} - 2 }{(x - 3) {}^{2} } = \\ = \frac{ {x}^{2} - 6x - 2 }{(x - 3) {}^{2} } [/tex]

Ответ: 3)