( (x^2-1,5x-7)/(x-4)^2 )> 0. Created by skellann. algebra-ru

(x-4)^2 )> 0...

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( (x^2-1,5x-7)/(x-4)^2 )> 0

vifi ((x^2-1,5x-7)/(x-4)^2)=0
2x^2-3x-14=0
D=(-3)^2-4*2*(-14)=121
x1=-2; x2=7/2
x∈(-∞, -2)⋃(3.5, 4)⋃(4, ∞)

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skellann а как же одз? )))