Объяснение:

[tex]x=0,5^{-1}\ \ \ \ \ x^{-2}=((0,5)^{-1})^{-2}=0,5^2=0,25.\\[/tex]

[tex]\frac{2x^{-2}}{1-x^{-2}}-\frac{2x^{-2}}{1+x^{-2}}=\frac{2*0,25}{1-0,25}-\frac{2*0,25}{1+0,25} =\frac{0,5}{0,75}-\frac{0,5}{1,25}=0,5*(\frac{1}{\frac{3}{4}}-\frac{1}{1\frac{1}{4} } } )=\\=0,5*(\frac{4}{3}-\frac{1}{\frac{5}{4} })=0,5*(\frac{4}{3} -\frac{4}{5})=0,5*\frac{4*5-4*3}{15} =0,5*\frac{20-12}{15} =\frac{1}{2} *\frac{8}{15} = \frac{4}{15}.[/tex]

[tex]x=0,5^{-1}=(\frac{1}{2})^{-1}=2.\\[/tex]