Ответ:
x²-4x-27>0
х1 = 2 - √31
x2 = 2 + √31
x є (-∞; 2 - √31) ∪ (2 + √31; +∞)
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Ответ:
x²-4x-27>0
х1 = 2 - √31
x2 = 2 + √31
x є (-∞; 2 - √31) ∪ (2 + √31; +∞)