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Юлияgaan
@Юлияgaan
August 2022
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Помогите пожалуйста, найдите производные следующих функций:
a) y = 1/√x
б) y = ∛x²
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IrkaShevko
Verified answer
Y' = (x^(-1/2))' = -1/2 * x^(-3/2) = 1/(2x√x)
y' = (x^(2/3))' = 2/3 * x^(-1/3) = 2/(3∛x)
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Alexandr130398
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Answers & Comments
Verified answer
Y' = (x^(-1/2))' = -1/2 * x^(-3/2) = 1/(2x√x)y' = (x^(2/3))' = 2/3 * x^(-1/3) = 2/(3∛x)