[tex]\displaystyle (x+1)^4(x-3)^4=32\\(x+1)(x-3)=б2\sqrt[4]{2}\\ x^2-3x+x-3=б2\sqrt[4]{2}\\ x^2-2x-3=б2\sqrt[4]{2}\\ x^2-2x-3=2\sqrt[4]{2};x^2-2x-3=-2\sqrt[4]{2}\\ x_1=1-\sqrt{4+2\sqrt[4]{2} },x_2=1-\sqrt{4-2\sqrt[4]{2} },x_3=1+\sqrt{4-2\sqrt[4]{2} },x_4=1+\sqrt{4+2\sqrt[4]{2} }[/tex]
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[tex]\displaystyle (x+1)^4(x-3)^4=32\\(x+1)(x-3)=б2\sqrt[4]{2}\\ x^2-3x+x-3=б2\sqrt[4]{2}\\ x^2-2x-3=б2\sqrt[4]{2}\\ x^2-2x-3=2\sqrt[4]{2};x^2-2x-3=-2\sqrt[4]{2}\\ x_1=1-\sqrt{4+2\sqrt[4]{2} },x_2=1-\sqrt{4-2\sqrt[4]{2} },x_3=1+\sqrt{4-2\sqrt[4]{2} },x_4=1+\sqrt{4+2\sqrt[4]{2} }[/tex]