(x+1)(x+2)(x+4)(x+5)=40Найдите сумму корней уравнения. Created by WANDERER20109. algebra-ru

(x+1)(x+2)(x+4)(x+5)=40Найдите сумму корней уравнения...

WANDERER20109 @WANDERER20109

July 2022 1 2 Report

(x+1)(x+2)(x+4)(x+5)=40
Найдите сумму корней уравнения

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Матов

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$(x+1)(x+2)(x+4)(x+5)=40\\
x^4+12x^3+49x^2+78x+40=40\\
x^4+12x^3+49x^2+78x=0\\
 x(x^3+12x^2+49x+78)=0\\
 x=0\\
x^3+12x^2+49x+78=0\\
x(x^2+6x+13)+6(x^2+6x+13)=0\\
(x+6)(x^2+6x+13)=0\\
x^2+6x+13=0\\
D$

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WANDERER20109 August 2022 | 0 Ответы

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WANDERER20109 July 2022 | 0 Ответы

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