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daryatulaeva
@daryatulaeva
July 2022
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(x^2-10)^2+12(x^2-10)+11=0
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nKrynka
Verified answer
X^2 - 10 = t
t^2 + 12t + 11 = 0
t1 = - 1
t2 = -11
1) x^2 - 10 = - 1
x^2 = 9
x1 = -3
x2 = 3
2) x^2 - 10 = - 11
x^2 = - 1 не имеет смысла
Ответ: х1 = -3; х2 = 3
1 votes
Thanks 4
AlxA
X1=(-b+sqrt(b^2-4ac))/2a=(-12+sqrt(144-4*11))/2=-1
X2=(-b- sqrt(b^2-4ac))/2a=(-12-sqrt(144-4*11))/2=-11
x^2-10=-1
x^2-9=0
x1=3
x2=-3
x^2-10=-11
x^2+1=0
корней нет
0 votes
Thanks 0
daryatulaeva
а он решается через дискриминант?
AlxA
да, конечно. Это ведь обычное квадратное уравнение.
daryatulaeva
спасибо
nKrynka
Уравнение t^2 + 12t + 11 = 0; t1 = - 1; t2 = -11
решается по теореме Виета
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Answers & Comments
Verified answer
X^2 - 10 = tt^2 + 12t + 11 = 0
t1 = - 1
t2 = -11
1) x^2 - 10 = - 1
x^2 = 9
x1 = -3
x2 = 3
2) x^2 - 10 = - 11
x^2 = - 1 не имеет смысла
Ответ: х1 = -3; х2 = 3
X2=(-b- sqrt(b^2-4ac))/2a=(-12-sqrt(144-4*11))/2=-11
x^2-10=-1
x^2-9=0
x1=3
x2=-3
x^2-10=-11
x^2+1=0
корней нет
решается по теореме Виета