(x^2+1)...

July 2022 1 6 Report

Найдите значение 2m – M, если m и M – значения функции в точке минимума и максимума, соответственно. f(x)=2x/(x^2+1)

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F(x)=2x/(x²+1)
f`(x)=(2x²+2-4x²)/(x²+1)²=(2-2x²)/(x²+1)²=2(1-x)(1+x)/(x²+1)=0
x=1 x=-1
_ + _
-------------------(-1)----------------(1)------------------
min max
m=f(-1)=-2/2=-1
M=f(1)=2/2=1
2m-M=2*(-1)-1=-2-1=-3

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Mikata98 спасибо большон

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(3sqrt(2\3)-sqrt(24)+sqrt(6))(2sqrt(2\3)+3*sqrt(2\3))...