Ответ:

[tex] {x}^{2} - 17x + 52 = 0 \\ d = {17}^{2} - 4 \times 52 = 289 - 208 = \\ = 81 = {9}^{2} \\ x1 = \frac{17 - 9}{2} = 4 \\ x2 = \frac{17 + 9}{2} = 13 \\ [/tex]

2)

[tex]x1^{2} + x2^{2} \\ {4}^{2} + {13 }^{2} = 16 + 169 = 185[/tex]

1)

[tex]x1 \times x2 \\ 4 \times 13 = 52[/tex]

3)

[tex]2704( \frac{1}{x1 ^{2} } + \frac{1}{x2 ^{2} } ) \\ 2704( \frac{1}{16} + \frac{1}{169} ) \\ 2704( \frac{169 + 16}{16 \times 169} ) \\ \frac{2704 \times 185}{16 \times 169} = 185[/tex]