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Vitalic55
@Vitalic55
July 2022
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Найти первообразные для функции:
y=x^3+2x^2,
y=2/x^3,
y=2sin3x,
y=2x^2-1/x^2
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Verified answer
y=x^3+2x^2,
F(x)=x^4/4 + 2x^3/3 + C
y=2/x^3,
F(x)=-1/x^2 + C
y=2sin3x,
F(x)=-2cos(3x)/3 + C
y=2x^2-1/x^2
F(x)=2x^3/3 - 1/x + C
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Verified answer
y=x^3+2x^2,F(x)=x^4/4 + 2x^3/3 + C
y=2/x^3,
F(x)=-1/x^2 + C
y=2sin3x,
F(x)=-2cos(3x)/3 + C
y=2x^2-1/x^2
F(x)=2x^3/3 - 1/x + C