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Решите систему уравнений
10x + 7y = 62, 12x - y = 18. В ответе запишите значение частного y/x
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exbntkm23
exbntkm23exbntkm23

10x + 7y = 62            10x + 7y = 62         10x + 7y = 62       10х+7(12х-18)=62

12x - y = 18                 12х=18+у                 у=12х-18               у=12х-18    

10х+84х-126=62        94х=188           х=2               х=2

у=12х-18                     у=12х-18          у=24-18         у=6

у/х=6/2=6:2=3

Ответ: 3

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