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shkalnyk
@shkalnyk
July 2022
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x^2+y^2+3xy=-1
x+2y=0
Решить методом подстановки
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AnonimusPro
Verified answer
Выражаем х из 2 уравнения: x=-2y, подставляем во 2: (-2y)^2+y^2+3y(-2y)=-1;
4y^2+y^2-6y^2=-1; -y^2=-1; y^2=1; y1=-1; y2=1;
x1=2; x2=-2; Ответ: (2;-1) и (-2;1)
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Answers & Comments
Verified answer
Выражаем х из 2 уравнения: x=-2y, подставляем во 2: (-2y)^2+y^2+3y(-2y)=-1;4y^2+y^2-6y^2=-1; -y^2=-1; y^2=1; y1=-1; y2=1;
x1=2; x2=-2; Ответ: (2;-1) и (-2;1)