Ответ:
(х-1)(х+4)
Объяснение:
x²+3x-4=0; х=1 и х=-4
x²+3x-4=(х-1)(х+4)
[tex]\displaystyle\bf\\x^{2} +3x-4=0\\\\Teorema \ Vieta:\\x_{1} +x_{2} =-3\\\\x_{1} \cdot x_{2} =-4\\\\x_{1} =-4\\\\x_{2} =1\\\\\\\boxed{x^{2} +3x-4=(x+4)(x-1)}[/tex]
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Ответ:
(х-1)(х+4)
Объяснение:
x²+3x-4=0; х=1 и х=-4
x²+3x-4=(х-1)(х+4)
[tex]\displaystyle\bf\\x^{2} +3x-4=0\\\\Teorema \ Vieta:\\x_{1} +x_{2} =-3\\\\x_{1} \cdot x_{2} =-4\\\\x_{1} =-4\\\\x_{2} =1\\\\\\\boxed{x^{2} +3x-4=(x+4)(x-1)}[/tex]