[tex]f(x) = \frac{1}{x**41}\\ f'(x) = - \frac{(x**41)'}{(x**41)^2} = - \frac{41x**40}{x**82 } = -\frac{41}{x**42}[/tex]
Ответ: -41/x^42
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
[tex]f(x) = \frac{1}{x**41}\\ f'(x) = - \frac{(x**41)'}{(x**41)^2} = - \frac{41x**40}{x**82 } = -\frac{41}{x**42}[/tex]
Ответ: -41/x^42