x^4...

Kir1906 @Kir1906

July 2022 1 10 Report

выполните сложение или вычитание
а)x/y^2+2/y
б)2x/y-x/y^2
в)1-a/a^2+1/a
г)x+a/x^2+x-a/ax
д)y+b/y^2+y+b/by
е)a-2b/ab^2-b-2a/a^2b
ж)c-d/c^2d-c+d/cd^2
з)a^2-b^2/b^5+2/b^3
и)x^3+1/x^7-1/x^4

Answers & Comments

Artem112

Verified answer

$\frac{x}{y^2}+ \frac{2}{y}= \frac{x+2y}{y^2}
\\\
 \frac{2x}{y} - \frac{x}{y^2}= \frac{2xy-x}{y^2} 
\\\
1- \frac{a}{a^2}+ \frac{1}{a}= 1- \frac{1}{a}+ \frac{1}{a}=1
\\\
x+ \frac{a}{x^2} +x- \frac{a}{ax}=2x+ \frac{a}{x^2} - \frac{x}{x^2}=\frac{2x^3+a-x}{x^2} 
\\\
y+ \frac{b}{y^2} +y+ \frac{b}{by} =2y+ \frac{b}{y^2} + \frac{y}{y^2} = \frac{2y^3b+y}{y^2} 
$
$a- \frac{2b}{ab^2}-b- \frac{2a}{a^2b}=a-b- \frac{2}{ab}- \frac{2}{ab}=
\frac{a^2b-ab^2-4}{ab}
\\\
c- \frac{d}{c^2d}-c+ \frac{d}{cd^2}= \frac{1}{cd}- \frac{1}{c^2}= \frac{c-d}{c^2d}
\\\
a^2- \frac{b^2}{b^5} + \frac{2}{b^3}=a^2- \frac{1}{b^3} + \frac{2}{b^3}=
a^2+ \frac{1}{b^3}= \frac{a^2b^3+1}{b^3}
\\\
x^3+ \frac{1}{x^7}- \frac{1}{x^4} = \frac{x^{10}+1-x^3}{x^7}$

8 votes Thanks 7

Answers & Comments

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