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Nuraika04
@Nuraika04
July 2022
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x^5+x^3 < x^3+1 решите метод интервалов пожалуйста
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Utem
X⁵+x³<x³+1
(x⁵+x³)/(x³+1)<1
(x⁵+x³)/(x³+1)-1<0
((x⁵+x³)-(x³+1))/(x³+1)<0
(x⁵+x³-x³-1)/(x³+1)<0
(x⁵-1)/(x³+1)<0
x⁵-1=0 x⁵=1 x=1
x³+1=0 x³≠-1 x≠-1 - знаменатель дроби не должен быть равен 0
+ - +
---------------------(-1)-------------------------(1)-----------------------------
х∈(-1;1)
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Answers & Comments
(x⁵+x³)/(x³+1)<1
(x⁵+x³)/(x³+1)-1<0
((x⁵+x³)-(x³+1))/(x³+1)<0
(x⁵+x³-x³-1)/(x³+1)<0
(x⁵-1)/(x³+1)<0
x⁵-1=0 x⁵=1 x=1
x³+1=0 x³≠-1 x≠-1 - знаменатель дроби не должен быть равен 0
+ - +
---------------------(-1)-------------------------(1)-----------------------------
х∈(-1;1)