x(x-3)^3-x(x-2)^3=-19x. Created by dimetrik02. algebra-ru

x(x-3)^3-x(x-2)^3=-19x...

konrad509

x(x-3)³-x(x-2)³=-19x

х(х³-9х²+27х-27)-х(х³-6х²+12х-8)=-19х

х⁴-9х³+27х²-27х-х⁴+6х³-12х²+8х=-19х

-3х³+15х²-19х =-19х

-3х³+15х²-19х + 19х = 0

-3х³+15х² = 0

-3х²(х-5)=0

х = 0 или х = 5

Ответ. х = 0, х = 5.

2 votes Thanks 1

ali07

Verified answer

$\\x(x-3)^3-x(x-2)^3=-19x\\ x(x^3-9x^2+27x-27)-x(x^3-6x^2+12x-8)=-19x\\ x^4-9x^3+27x^2-27x-x^4+6x^3-12x^2+8x=-19x\\ -3x^3+15x^2=0\\ -3x^2(x-5)=0\\ x=0 \vee x=5\\$

0 votes Thanks 2

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