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AhnSoHee
@AhnSoHee
July 2022
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Я безбожно туплю. Помогите
2sin^2 x(3пи+x) = (корень 3) cosx
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mayasychyk
2SIN^2(3PI/2+X)=2COS^2(X)
2COS^2X=√3COSX
COSX(2COSX-√3)=0
COSX=0
X=PI/2+PI*K K∈Z
COSX=√3/2
X=+-PI/6+2PI*N N∈Z
2 votes
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Answers & Comments
2COS^2X=√3COSX
COSX(2COSX-√3)=0
COSX=0
X=PI/2+PI*K K∈Z
COSX=√3/2
X=+-PI/6+2PI*N N∈Z