F=10H, r=8мм=8*10⁻³м
σ-?
σ=F/l, l=2πr
⇒ σ=F/2πr
σ = 10 / 2*3,14*8*10⁻³ = 10⁴/50,24 ≈ 199 Н/м
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F=10H, r=8мм=8*10⁻³м
σ-?
σ=F/l, l=2πr
⇒ σ=F/2πr
σ = 10 / 2*3,14*8*10⁻³ = 10⁴/50,24 ≈ 199 Н/м