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AlexHoroshiy
@AlexHoroshiy
July 2022
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y=x^3 + 3x^2+4
помогите н
айти промежутки возрастания и убывания функции
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ammerzium234
y=x^3 + 3x^2+4
(y)'=3x^2+6x
3x(x+2)=0
3x=0 и x+2=0
x=0 и x=-2
2 votes
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Answers & Comments
(y)'=3x^2+6x
3x(x+2)=0
3x=0 и x+2=0
x=0 и x=-2