Стандартный вид числа
a = b*10^n (1 < b < 10)
12000000 = 1.2 * 10⁷
(5/6a)⁻² * 2a³ * (4/5)⁰ / ((1.2a)² * a⁻³)
(4/5)⁰ = 1
(5/6a)⁻² = (6/5)² * a⁻²
(1.2a)² = (6/5)²*a²
(6/5)² * a⁺² * 2a³ / ( (6/5)² * a² * a⁻³)) = 2a²
2*(12000000)² = 2.88*10¹⁴
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Verified answer
Стандартный вид числа
a = b*10^n (1 < b < 10)
12000000 = 1.2 * 10⁷
(5/6a)⁻² * 2a³ * (4/5)⁰ / ((1.2a)² * a⁻³)
(4/5)⁰ = 1
(5/6a)⁻² = (6/5)² * a⁻²
(1.2a)² = (6/5)²*a²
(6/5)² * a⁺² * 2a³ / ( (6/5)² * a² * a⁻³)) = 2a²
2*(12000000)² = 2.88*10¹⁴