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kdyrdias2008
@kdyrdias2008
August 2021
0
21
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Заполни пропуски так, чтобы получилось верное равенство.
(...
a3 + 3a2 – 2a +...
) + (4a2 – 5) + (2a3 + 2a + 3) = 3a3 +...
a2 + 9
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