–х²–2х+15=0;
х²+2х–15=0.
Для данного уравнения а=1, b=2, c=–15.
D= b²–4ac= 2²–4•1•(–15)= 4+60= 64= 8².
x1= (–b+√D)/2a= (–2+8):2= 6:2= 3.
x2= (–b–√D)/2a= (–2–8):2= (–10):2= –5.
ОТВЕТ: –5; 3.
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Answers & Comments
–х²–2х+15=0;
х²+2х–15=0.
Для данного уравнения а=1, b=2, c=–15.
D= b²–4ac= 2²–4•1•(–15)= 4+60= 64= 8².
x1= (–b+√D)/2a= (–2+8):2= 6:2= 3.
x2= (–b–√D)/2a= (–2–8):2= (–10):2= –5.
ОТВЕТ: –5; 3.