(2 - x)(2 + x)(x - 1) + x²(x - 1) =( 4 - x²)*(x - 1) + x³ - x² = 4x - 4 - x³ + x² + x³ - x² =
= 4x - 4
x = 1,8 ⇒ 4x - 4 = 4 * 1,8 - 4 = 7,2 - 4 = 3,2
Ответ:
(2-х)(2+х)(х-1)+х^2(х-1)
(х-1)×((2-х)(2+х)+х^2)
(х-1)×(4-х^2+х^2)
(х-1)×4
(1.8-1)×4
0.8×4=3.2
ответ: 3.2
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Verified answer
(2 - x)(2 + x)(x - 1) + x²(x - 1) =( 4 - x²)*(x - 1) + x³ - x² = 4x - 4 - x³ + x² + x³ - x² =
= 4x - 4
x = 1,8 ⇒ 4x - 4 = 4 * 1,8 - 4 = 7,2 - 4 = 3,2
Ответ:
(2-х)(2+х)(х-1)+х^2(х-1)
(х-1)×((2-х)(2+х)+х^2)
(х-1)×(4-х^2+х^2)
(х-1)×4
(1.8-1)×4
0.8×4=3.2
ответ: 3.2