Відповідь:
1)5√a2)6√53) [tex]-5\frac{1}{3} \sqrt{3b}[/tex]
Покрокове пояснення:
1)
[tex]\sqrt{16a}+\sqrt{100a}-\sqrt{81a}=\sqrt{x4^2a}+\sqrt{10^2a}-\sqrt{9^2a}=4\sqrt{a} +10\sqrt{a} -9\sqrt{a}=\sqrt{a}(4+10-9)=5\sqrt{a}[/tex]
2)
[tex]=\sqrt{4*5}-\sqrt{25*5}+\sqrt{81*5}=\sqrt{2^2*5}-\sqrt{5^2*5}+\sqrt{9^2*5}=2\sqrt{5}-5\sqrt{5}+9\sqrt{5}= 6\sqrt{5}[/tex]
3)
[tex]=4\sqrt{9*3b}-5\sqrt{16*3b}+\frac{1}{3}\sqrt{64*3b}=12\sqrt{3b}-20\sqrt{3b}+\frac{8}{3} \sqrt{3b}=\sqrt{3b}(\frac{36-60+8}{3} ) = -\frac{16}{3}\sqrt{3b}= -5\frac{1}{3}\sqrt{3b}[/tex]
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Verified answer
Відповідь:
1)5√a
2)6√5
3) [tex]-5\frac{1}{3} \sqrt{3b}[/tex]
Покрокове пояснення:
1)
[tex]\sqrt{16a}+\sqrt{100a}-\sqrt{81a}=\sqrt{x4^2a}+\sqrt{10^2a}-\sqrt{9^2a}=4\sqrt{a} +10\sqrt{a} -9\sqrt{a}=\sqrt{a}(4+10-9)=5\sqrt{a}[/tex]
2)
[tex]=\sqrt{4*5}-\sqrt{25*5}+\sqrt{81*5}=\sqrt{2^2*5}-\sqrt{5^2*5}+\sqrt{9^2*5}=2\sqrt{5}-5\sqrt{5}+9\sqrt{5}= 6\sqrt{5}[/tex]
3)
[tex]=4\sqrt{9*3b}-5\sqrt{16*3b}+\frac{1}{3}\sqrt{64*3b}=12\sqrt{3b}-20\sqrt{3b}+\frac{8}{3} \sqrt{3b}=\sqrt{3b}(\frac{36-60+8}{3} ) = -\frac{16}{3}\sqrt{3b}= -5\frac{1}{3}\sqrt{3b}[/tex]