1.у'=d/dx(-2cos(x/2+n/3)+3)
2.y'=d/dx(-2cos(x/2+n/3))+d/dx(3)
3.y'=-2x(sin(x/2+n/3)×1/2)+0
ответ
y'=sin(x/2)+√3cos(x/2)/2
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Answers & Comments
1.у'=d/dx(-2cos(x/2+n/3)+3)
2.y'=d/dx(-2cos(x/2+n/3))+d/dx(3)
3.y'=-2x(sin(x/2+n/3)×1/2)+0
ответ
y'=sin(x/2)+√3cos(x/2)/2