Ответ: x∈(-1/2;+∞).
Объяснение:
[tex]\displaystyle\\16^x > 0,25\\\\(4^2)^x > \frac{1}{4} \\\\4^{2x} > 4^{-1}\ \ \ \ \ \ \Rightarrow\\\\2x > -1\ |:2\\\\x > -\frac{1}{2} .[/tex]
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Ответ: x∈(-1/2;+∞).
Объяснение:
[tex]\displaystyle\\16^x > 0,25\\\\(4^2)^x > \frac{1}{4} \\\\4^{2x} > 4^{-1}\ \ \ \ \ \ \Rightarrow\\\\2x > -1\ |:2\\\\x > -\frac{1}{2} .[/tex]