1) (x-1)(x-3)(x-5)>0x²-3x-x+3x+3>0x ∈ (1,3) ∪ (5,∞)2) (х+1)(х-1)(х-2)>0
x²-1(x-2)>0х ∈ (−1,1) ∪ (2,∞)
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1) (x-1)(x-3)(x-5)>0
x²-3x-x+3x+3>0
x ∈ (1,3) ∪ (5,∞)
2) (х+1)(х-1)(х-2)>0
x²-1(x-2)>0
х ∈ (−1,1) ∪ (2,∞)