Объяснение:
1.
arccos√3/2+arctg(tg4π/7)+
+arcctg(ctg(-π/4))=kπ
π/6+arctg(-tg(3π/7))+arcctg(ctg(7π/4))=πk
π/6-arctg(tg(3π/7))+arcctg(-ctg(π/4))=πk
π/6-3π/7+π-arcctg(ctg(π/4))=πk
π/6-3π/7+π-π/4=πk
14π/84-36π/84+84π/84-21π/84=πk
41π/84=πk
84πk=41π
k=41/84
ответ: k=41/84
2.
8arccos²x+2πarccosx-π²=0 ; x∈[-1;1]
arccos=t
8t²+2πt-π²=0
D=(2π)²-4×8×(-π²)=4π²+32π²=36π²
t1=(-2π+6π)/16=π/4
t2=(-2π-6π)/16= -π/2
arccosx=π/4 ; x=cosπ/4=√2/2
arccosx= -π/2 ; ø ,т.к х∈[0;π]
ответ: √2/2
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Verified answer
Объяснение:
1.
arccos√3/2+arctg(tg4π/7)+
+arcctg(ctg(-π/4))=kπ
π/6+arctg(-tg(3π/7))+arcctg(ctg(7π/4))=πk
π/6-arctg(tg(3π/7))+arcctg(-ctg(π/4))=πk
π/6-3π/7+π-arcctg(ctg(π/4))=πk
π/6-3π/7+π-π/4=πk
14π/84-36π/84+84π/84-21π/84=πk
41π/84=πk
84πk=41π
k=41/84
ответ: k=41/84
2.
8arccos²x+2πarccosx-π²=0 ; x∈[-1;1]
arccos=t
8t²+2πt-π²=0
D=(2π)²-4×8×(-π²)=4π²+32π²=36π²
t1=(-2π+6π)/16=π/4
t2=(-2π-6π)/16= -π/2
arccosx=π/4 ; x=cosπ/4=√2/2
arccosx= -π/2 ; ø ,т.к х∈[0;π]
ответ: √2/2
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