[tex]\frac{x^2+2x-15}{x^2-9}=\\\\=\frac{(x+3)(x-5)}{(x-3)(x+3)}=\\\\=\frac{x+3}{x-3}*\frac{x-5}{x+3}=\\\\=\frac{x+3}{x+3}*\frac{x-5}{x-3}=\\\\=\frac{(x+3)(x-5)}{x-3}*\frac{1}{x+3}=\\\\=\frac{1}{x-3}*\frac{(x+3)(x-5)}{x+3}=\\\\=\frac{x^2+2x-15}{(x+3)}*\frac{1}{x-3}=\\\\=\frac{1}{x+3}*\frac{x^2+2x-15}{x-3}[/tex]
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x²+2x-15=(x+3)(x-5) по теореме Виета
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[tex]\frac{x^2+2x-15}{x^2-9}=\\\\=\frac{(x+3)(x-5)}{(x-3)(x+3)}=\\\\=\frac{x+3}{x-3}*\frac{x-5}{x+3}=\\\\=\frac{x+3}{x+3}*\frac{x-5}{x-3}=\\\\=\frac{(x+3)(x-5)}{x-3}*\frac{1}{x+3}=\\\\=\frac{1}{x-3}*\frac{(x+3)(x-5)}{x+3}=\\\\=\frac{x^2+2x-15}{(x+3)}*\frac{1}{x-3}=\\\\=\frac{1}{x+3}*\frac{x^2+2x-15}{x-3}[/tex]
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x²+2x-15=(x+3)(x-5) по теореме Виета