[tex]y = {x}^{2} ( {x}^{3} - 1) \\ y' = ( {x}^{2} )'( {x}^{3} - 1) + {x}^{2} ( {x}^{3} - 1)' = \\ = 2x( {x}^{3 } - 1) + {x}^{2} \times 3 {x}^{2} = \\ = 2 {x}^{4} - 2x + 3x {}^{4} = 5x {}^{4} - 2x[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
[tex]y = {x}^{2} ( {x}^{3} - 1) \\ y' = ( {x}^{2} )'( {x}^{3} - 1) + {x}^{2} ( {x}^{3} - 1)' = \\ = 2x( {x}^{3 } - 1) + {x}^{2} \times 3 {x}^{2} = \\ = 2 {x}^{4} - 2x + 3x {}^{4} = 5x {}^{4} - 2x[/tex]