Ответ: 1

Объяснение:

[tex]=\sqrt[6]{(1-\sqrt{2})^2*(3+2\sqrt{2}) } =\sqrt[6]{(1-2\sqrt{2}+2)*(3+2\sqrt{2}) } =\sqrt[6]{(3-2\sqrt{2})*(3+2\sqrt{2}) } =\sqrt[6]{3^2-(2\sqrt{2})^2}=\sqrt[6]{9-4*2}=\sqrt[6]{9-8}=\sqrt[6]{1}=1[/tex]