Ответ:
[tex]171[/tex]
Объяснение:
[tex]\displaystyle \int_{-1}^{8}x^2 dx=\frac{1}{3}x^3\Big|^8_{-1}=\frac{1}{3}\cdot 8^3-\frac{1}{3}\cdot(-1)^3=\frac{1}{3}\cdot 512-\frac{1}{3}\cdot(-1)=\\\\\\\frac{512}{3}+\frac{1}{3}=\frac{513}{3}=171[/tex]
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Ответ:
[tex]171[/tex]
Объяснение:
[tex]\displaystyle \int_{-1}^{8}x^2 dx=\frac{1}{3}x^3\Big|^8_{-1}=\frac{1}{3}\cdot 8^3-\frac{1}{3}\cdot(-1)^3=\frac{1}{3}\cdot 512-\frac{1}{3}\cdot(-1)=\\\\\\\frac{512}{3}+\frac{1}{3}=\frac{513}{3}=171[/tex]