[tex]x - y = 1 \\ x {}^{2} - y {}^{2} = 8 \\ \\ x = y + 1 \\ (y + 1) {}^{2} - {y}^{2} = 8 \\ \\ {y}^{2} + 2y + 1 - {y}^{2} = 8 \\ 2y = 8 - 1 \\ 2y = 7 \\ y = 7 \div 2 \\ y = 3.5 \\ \\ x = 3.5 + 1 = 4.5[/tex]
Ответ: ( 4,5 ; 3,5 )
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[tex]x - y = 1 \\ x {}^{2} - y {}^{2} = 8 \\ \\ x = y + 1 \\ (y + 1) {}^{2} - {y}^{2} = 8 \\ \\ {y}^{2} + 2y + 1 - {y}^{2} = 8 \\ 2y = 8 - 1 \\ 2y = 7 \\ y = 7 \div 2 \\ y = 3.5 \\ \\ x = 3.5 + 1 = 4.5[/tex]
Ответ: ( 4,5 ; 3,5 )