Ответ:
BC=x
[tex] {x}^{2} = {4}^{2} + {6}^{2} - 2 \times 4 \times 6 \times \cos( {60}^{ \circ} ) \\ {x}^{2} = 24 + 36 - 48 \times \frac{1}{2} \\ {x}^{2} = 60 - 24 \\ {x}^{2} = 36 \\ x = \sqrt{36} \\ x = 6[/tex]
BC=6
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Ответ:
BC=x
[tex] {x}^{2} = {4}^{2} + {6}^{2} - 2 \times 4 \times 6 \times \cos( {60}^{ \circ} ) \\ {x}^{2} = 24 + 36 - 48 \times \frac{1}{2} \\ {x}^{2} = 60 - 24 \\ {x}^{2} = 36 \\ x = \sqrt{36} \\ x = 6[/tex]
BC=6