(sin pi/8 - cos pi/8)^2 =? (sin pi/12 + cos pi/12)^2=?. Created by Arrrani. algebra-ru

12)^2=?...

Arrrani @Arrrani

May 2022 1 9 Report

(sin pi/8 - cos pi/8)^2 =?
(sin pi/12 + cos pi/12)^2=?

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sedinalana

Verified answer

(sin pi/8 - cos pi/8)^2 =sin²π/8+cos²π/8-2sinπ/8cosπ/8=1-sinπ/4=1-√2/2=
=(2-√2)/2

(sin pi/12 + cos pi/12)^2=sin²π/12+cos²π/12+2sinπ/12cosπ/12=1+sinπ/6=
=1+1/2=1,5

2 votes Thanks 0

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