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Arrrani
@Arrrani
July 2022
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ПОМОГИТЕ, ПОЖАЛУЙСТА
cos (a+b)cos (a-b)+sin(a+b)sin(a-b)= ?
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Answers & Comments
армения20171
Cos(a+b)cos(a-b)+sin(a+b)sin(a-b)=
cos(a+b-(a-b))=cos(a+b-a+b)=cos(2b)
4 votes
Thanks 2
Arrrani
можешь еще с одним помочь?
армения20171
скажите
Arrrani
(sin(a+b)-cos a*sin b) : ( cos (a-b)- sin a*sinb )
армения20171
1)sin(a+b)-cosa•sinb=sina•cosb+cosa•sinb-cosa•sinb=sina•cosb 2)cosa•cosb+sina•sinb-sina•sinb=cosa•cosb 3)sina•cosb/(cosa•cosb)=sina/cosa=tga
Arrrani
Спасибо!
sedinalana
cos (a+b)cos (a-b)+sin(a+b)sin(a-b)=сos(a+b-a+b)=cos2b
-------------------------------
cosxcosy+sinxsiny=cos(x-y)
2 votes
Thanks 3
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Answers & Comments
cos(a+b-(a-b))=cos(a+b-a+b)=cos(2b)
-------------------------------
cosxcosy+sinxsiny=cos(x-y)