Объяснение:
соsα=√(1-sin²α)=√(1-(5/13)²)=
=√(1-(25/169))=√(144/169)=12/13
tgα=sinα/cosα=5/13:12/13=5/13•13/12=5/12
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Объяснение:
соsα=√(1-sin²α)=√(1-(5/13)²)=
=√(1-(25/169))=√(144/169)=12/13
tgα=sinα/cosα=5/13:12/13=5/13•13/12=5/12