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Artem32481
@Artem32481
July 2022
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sin L = 5/13 , сколько будет sin2L, cos2L,tg2L,ctg2L.
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sedinalana
Verified answer
СosL=+-√(1-sin²a)=+-√(1-25/169)=+-√(144/169)=+-12/13
sin2a=2sinacosa=2*5/13*12/13=120/169
cos2a=cos²a-sin²a=144/169-25/169=119/169
tg2a=sin2a/cos2a=120/169:119/169=120/169*169/119=120/119
ctg2a=1/tg2a=119/120
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Answers & Comments
Verified answer
СosL=+-√(1-sin²a)=+-√(1-25/169)=+-√(144/169)=+-12/13sin2a=2sinacosa=2*5/13*12/13=120/169
cos2a=cos²a-sin²a=144/169-25/169=119/169
tg2a=sin2a/cos2a=120/169:119/169=120/169*169/119=120/119
ctg2a=1/tg2a=119/120