Verified answer

(Решение первой системы представлено во вложении)
Ответ: (х;у) = (2;1)
2) [tex]\displaystyle \left \{ {{6x+y=10} \atop {6x-3y=-26}} \right. < = > \left \{ {{y=10-6x} \atop {6x-3(10-6x)=-26}} \right. < = > \left \{ {{y=10-6x} \atop {6x-30+18x=-26}} \right. < = > \left \{ {{y=10-6x} \atop {6x+18x=-26+30}} \right. < = > \left \{ {{y=10-6x} \atop {24x=4|:24}} \right. < = > \left \{ {{y=10-6*\frac{1}{6} } \atop {x=\frac{1}{6} }} \right. < = > \left \{ {{y=10-1 } \atop {x=\frac{1}{6} }} \right. < = > \left \{ {{y=9 } \atop {x=\frac{1}{6} }} \right.[/tex]

Ответ: (х;у) = (1/6;9)