Ответ:

Дано:

t_1=-10Ct

1

=−10C

t_2=0Ct

2

=0C

t_3=100Ct

3

=100C

m=2kgm=2kg

C_1=2100 \frac{Dg}{kg*C}C

1

=2100

kg∗C

Dg

C_2=4200 \frac{Dg}{kg*c}C

2

=4200

kg∗c

Dg

λ =340000 \frac{Dg}{kg}=340000

kg

Dg

L=2300000 \frac{Dg}{kg}L=2300000

kg

Dg

-----−−−−−

Q-?Q−?

Решение:

Q=Q_1+Q_2+Q_3+Q_4Q=Q

1

+Q

2

+Q

3

+Q

4

Q_1=C_1m(t_2-t_1)Q

1

=C

1

m(t

2

−t

1

)

Q_2=Q

2

= λ mm

Q_3=C_2m(t_3-t_2)Q

3

=C

2

m(t

3

−t

2

)

Q_4=LmQ

4

=Lm

Q_2=2100 \frac{Dg}{kg*C}*2kg*(0-(-10C)=42000DgQ

2

=2100

kg∗C

Dg

∗2kg∗(0−(−10C)=42000Dg

Q_2=340000 \frac{Dg}{kg}*2kg=680000DgQ

2

=340000

kg

Dg

∗2kg=680000Dg

Q_3=4200 \frac{Dg}{kg*c}*2kg*(100C-0C)= 840000DgQ

3

=4200

kg∗c

Dg

∗2kg∗(100C−0C)=840000Dg

Q_4=2300000 \frac{Dg}{kg}*2kg=4600000DgQ

4

=2300000

kg

Dg

∗2kg=4600000Dg Q=42000Dg+680000Dg+840000Dg+4600000Dg=6162000DgQ=42000Dg+680000Dg+840000Dg+4600000Dg=6162000Dg =6162kDg=6162kDg

Ответ:Q=6162kDgQ=6162kDg

Объяснение:

ну так вроде