Пошаговое объяснение:
S=|∫³(4-12/х)dx|
²
∫³(4-12/x)dx=∫4dx-∫(12/x)dx=
=(4x-12ln|x|)|³= 4•3-12ln|3|-(4•2-12ln|2|)=
=12-12ln|3|-8+12ln|2|=4+12ln(2/3)
S=|4+12ln(2/3)|= -(4+12ln(2/3)=
= -4-12ln(2/3)= -4-12•(-0,4)=0,8 eд²
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Verified answer
Пошаговое объяснение:
S=|∫³(4-12/х)dx|
²
∫³(4-12/x)dx=∫4dx-∫(12/x)dx=
²
=(4x-12ln|x|)|³= 4•3-12ln|3|-(4•2-12ln|2|)=
²
=12-12ln|3|-8+12ln|2|=4+12ln(2/3)
S=|4+12ln(2/3)|= -(4+12ln(2/3)=
= -4-12ln(2/3)= -4-12•(-0,4)=0,8 eд²