Ответ:

Пошаговое объяснение:

[tex]5^{\frac{1}{2} } = \sqrt[]{5}}[/tex]

[tex]3^{\frac{2}{3} } = \sqrt[3]{3^{2}}[/tex]

[tex]10^{-\frac{1}{4} } = \sqrt[4]{0.1}[/tex]

[tex]17^{-\frac{1}{5} } = \sqrt[5]{\frac{1}{17} }[/tex]

[tex]x^{0.5 } = x^{\frac{1}{2}} = \sqrt[]{x}[/tex]

[tex]y^{1.5 } = y^{\frac{3}{2}} = \sqrt[]{y^3}[/tex]

[tex]b^{-0.5 } = b^{-\frac{1}{2}} = \sqrt[]{\frac{1}{b}}[/tex]

[tex]c^{-2.5 } = c^{-\frac{5}{2}} = \sqrt[]{\frac{1}{c^5}}[/tex]

[tex]5x^{\frac{1}{4}} = 5\sqrt[4]{x}[/tex]

[tex]-3y^{\frac{2}{3}} = -3 \sqrt[3]{y^2}[/tex]

[tex](3b)^{-1.5} = (3b)^{-\frac{3}{2}} =\frac{1}{(3b)^{\frac{3}{2}}} = \sqrt[]{\frac{1}{(3b)^3}}[/tex]

[tex](2a)^{0.2} = (2a)^{\frac{1}{5}} = \sqrt[5]{2a}[/tex]