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vipsmile666
@vipsmile666
August 2022
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2 задачи по физике. Нужно нормально расписать и каждой задаче график или рисунок, в зависимости от условия
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Verified answer
M1v =(m1+m2)*u
m1a1=-F
a1=-F/m1
t=(u-v)/a1=-m1*(m1*v/(m1+m2)-v)/F=m1*m2*v/((m1+m2)*F)
m2a2=F
a2=F/m2
S=(v*t+a1*t^2/2) - (0*t+a2*t^2/2)=v*t+(a1-a2)*t^2/2
S=v^2/(2*F(1/m1+1/m2))
m1=1/(v^2/(2*F*S)-1/m2)=1/(500^2/(2*18000*0,15)-1/5) кг =
0,021693717
кг ~0,0217кг ~ 0,022кг = 22 г
p1V1/T1=p2V2/T2=p3V3/T3
V3=V1*p1/p2*T3/T1=3*10^6/(1,9*10^6)*570/450 л = 2 л
V2=V3= 2л
p2=p1=1 Мпа
T2=T1 * (p2/p1) * (V2/V1) = 450 * (10^6/10^6) * (2/3) К =300 К
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Answers & Comments
Verified answer
M1v =(m1+m2)*um1a1=-F
a1=-F/m1
t=(u-v)/a1=-m1*(m1*v/(m1+m2)-v)/F=m1*m2*v/((m1+m2)*F)
m2a2=F
a2=F/m2
S=(v*t+a1*t^2/2) - (0*t+a2*t^2/2)=v*t+(a1-a2)*t^2/2
S=v^2/(2*F(1/m1+1/m2))
m1=1/(v^2/(2*F*S)-1/m2)=1/(500^2/(2*18000*0,15)-1/5) кг = 0,021693717кг ~0,0217кг ~ 0,022кг = 22 г
p1V1/T1=p2V2/T2=p3V3/T3
V3=V1*p1/p2*T3/T1=3*10^6/(1,9*10^6)*570/450 л = 2 л
V2=V3= 2л
p2=p1=1 Мпа
T2=T1 * (p2/p1) * (V2/V1) = 450 * (10^6/10^6) * (2/3) К =300 К